LinkedList同时实现了List接口和Deque接口,也就是说它既可以看作一个顺序容器,又可以看作一个队列(Queue),同时又可以看作一个栈(Stack)。
LinkedList类图
transient int size = 0;
/**
* first始终不变:
* 1、集合没有元素:first == null && last == null
* 2、集合添加了元素:first.prev == null && first.item != null
*/
transient Node first;
/**
* last始终不变:
* 1、集合没有元素:first == null && last == null
* 2、集合添加了元素:(last.next == null && last.item != null)
*/
transient Node last;
private static class Node {
E item;
Node next;
Node prev;
Node(Node prev, E element, Node next) {
this.item = element;
this.next = next;
this.prev = prev;
}
}
/**
* 构造一个空集合
*/
public LinkedList() {
}
//添加元素到链表末尾
public boolean add(E e) {
linkLast(e);
return true;
}
/**
* first last
* first a b last
*
*/
void linkLast(E e) {
final Node l = last;
//创建节点
final Node newNode = new Node<>(l, e, null);
//last始终指向尾节点
last = newNode;
//首次添加元素
if (l == null)
//first始终指向头节点
first = newNode;
else
l.next = newNode;
size++;
modCount++;
}
private static class Node {
E item;
Node next;
Node prev;
Node(Node prev, E element, Node next) {
this.item = element;
this.next = next;
this.prev = prev;
}
}
public void add(int index, E element) {
checkPositionIndex(index);
//如果index=size,直接在末尾添加,等同于add(e)方法
if (index == size)
linkLast(element);
else
linkBefore(element, node(index));
}
/**
* 返回需要修改节点的位置
*/
Node node(int index) {
//根据当前添加元素的位置判断是从头开始找还是尾开始找
if (index < (size >> 1)) {
Node x = first;
for (int i = 0; i < index; i++)
x = x.next;
return x;
} else {
Node x = last;
for (int i = size - 1; i > index; i--)
x = x.prev;
return x;
}
}
/**
* 将前一个节点next->newNode
* 将后一个节点pre->newNode
*/
void linkBefore(E e, Node succ) {
// assert succ != null;
final Node pred = succ.prev;
final Node newNode = new Node<>(pred, e, succ);
succ.prev = newNode;
if (pred == null)
first = newNode;
else
pred.next = newNode;
size++;
modCount++;
}
add操作
public E getFirst() {
final Node f = first;
if (f == null)
throw new NoSuchElementException();
return f.item;
}
public E getLast() {
final Node l = last;
if (l == null)
throw new NoSuchElementException();
return l.item;
}
public boolean remove(Object o) {
if (o == null) {
for (Node x = first; x != null; x = x.next) {
if (x.item == null) {
unlink(x);
return true;
}
}
} else {
for (Node x = first; x != null; x = x.next) {
if (o.equals(x.item)) {
unlink(x);
return true;
}
}
}
return false;
}
E unlink(Node x) {
// assert x != null;
final E element = x.item;
final Node next = x.next;
final Node prev = x.prev;
if (prev == null) {
first = next;
} else {
prev.next = next;
x.prev = null;
}
if (next == null) {
last = prev;
} else {
next.prev = prev;
x.next = null;
}
x.item = null;
size--;
modCount++;
return element;
}
remove操作
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